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( i ) Pressure = area.
(ii) frequent collisions with the walls.
Less exerted on walls.
P1 = P2V2 .
= 1.0 x 10 ^ 5 x x 10 ^ -4 / 1.8 x 10 ^ -4.
= x 10 ^ 5 Pa. ( final answer )
No escape.
The gas faster and gain energy .
Pressure and larger a of gas.
collide the walls (of the cylinder) , force on (causes) .
The closer gas will collide more frequently with the of the rubber chamber resulting in the pressure.
of infra-red radiation
energy absorbed
Pressure .
frequent molecular collisions with .
W = g .
= 70 x .
= N. ( final answer )
P = F .
= / ( 35 x 4 )
= .
( final answer )
( i ) collide with the walls (of the cylinder) , (causes) on walls .
( ii ) closer in given .
More collisions per unit .
( i ) of molecules .
( ii ) Fewer collisions of needed .
rises initially.